2x^2-5=3x^2x+31

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Solution for 2x^2-5=3x^2x+31 equation: 



2x^2-5=3x^2x+31

We move all terms to the left:

2x^2-5-(3x^2x+31)=0

We get rid of parentheses

2x^2-3x^2x-31-5=0

We add all the numbers together, and all the variables

2x^2-3x^2x-36=0

We move all terms containing x to the left, all other terms to the right

2x^2-3x^2x=36

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